T(n)=n^2+4n+3

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Solution for T(n)=n^2+4n+3 equation: 



(T)=T^2+4T+3

We move all terms to the left:

(T)-(T^2+4T+3)=0

We get rid of parentheses

-T^2+T-4T-3=0

We add all the numbers together, and all the variables

-1T^2-3T-3=0

a = -1; b = -3; c = -3;
Δ = b2-4ac
Δ = -32-4·(-1)·(-3)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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